Question

Question #5b0b1

Answer 1

`105m`

Explanation:

Using the applicable kinematic expression

`h=ut+1/2g t^2`
where `h` is the height after time `t`. `u` is initial velocity and `g` is acceleration due to gravity.

Inserting giving numbers and remembering that gravity is acting against the direction of motion

`h=50xx7+1/2(-10) (7)^2`
`=>h=350-245`
`=>h=105m`