Question #70e44
1 Answer
Apr 16, 2017
Explanation:
Case
#3m = m^2 - 10#
#0 = m^2 - 3m - 10#
#0 = (m - 5)(m + 2)#
#m = 5 or -2#
Case
#3m = -(m^2 - 10)#
#3m = -m^2 +10#
#m^2 + 3m - 10 = 0#
#(m + 5)(m - 2) = 0#
#m = -5 or 2#
However, the negative solutions are extraneous because the left hand side would be negative while the right hand side would be positive (by the definition of
Hopefully this helps!