Question #3828f

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Answer 1 · 2017-04-17T15:28:07

See below.

$a x^2+bx+c = a(x^2+b/ax+c/a)$

and now

$x =1/2 (-b/apm sqrt((b/a)^2-4(c/a)))$

or

$ax^2+bx+c=a(x+b/(2a)+1/2sqrt((b/a)^2-4(c/a)))(x+b/(2a)-1/2sqrt((b/a)^2-4(c/a)))$

or

$ax^2+bx+c=a(x+b/(2a)+1/(2absa)sqrt(b^2-4ac))(x+b/(2a)-1/(2absa)sqrt(b^2-4ac))$