# What mass of solute is present in 24*mL of 0.10*mol*l^-1 aqueous sodium chloride solution?

Apr 23, 2017

Approx. $0.140 \cdot g$.

#### Explanation:

We have $0.1 \cdot m o l \cdot {\mathrm{dm}}^{-} 3$ $N a C l$.

Now believe or not, $1 \cdot {\mathrm{dm}}^{3} = 1 \cdot L$, because the prefix $\text{deci} \equiv {10}^{-} 1$

And so,...........$1 \cdot {\mathrm{dm}}^{3} = {\left(1 \times {10}^{-} 1 \cdot m\right)}^{3}$

$= 1 \times {10}^{-} 3 \cdot {m}^{3} \equiv 1 \cdot L$, because there are $1000 \cdot L$ in a ${m}^{3}$. A $\text{cubic meter}$ is A HUGE VOLUME..........

And so we simply perform the product:

$\text{Mass of NaCl"="Concentration"xx"Volume"xx"molar mass, NaCl}$

$0.024 \cdot L \times 0.1 \cdot m o l \cdot {L}^{-} 1 \times 58.44 \cdot g \cdot m o {l}^{-} 1 = 0.140 \cdot g$.