What mass of solute is present in $24mL$ of $0.10mol*l^-1$ aqueous sodium chloride solution?

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Answer 1 · 2017-04-23T15:28:38

Approx. $0.140*g$ .

We have $0.1*mol*dm^-3$ $NaCl$ .

Now believe or not, $1*dm^3=1*L$ , because the prefix $"deci"-=10^-1$

And so,........... $1*dm^3=(1xx10^-1*m)^3$

$=1xx10^-3*m^3-=1*L$ , because there are $1000*L$ in a $m^3$ . A $"cubic meter"$ is A HUGE VOLUME..........

And so we simply perform the product:

$"Mass of NaCl"="Concentration"xx"Volume"xx"molar mass, NaCl"$

$0.024*Lxx0.1*mol*L^-1xx58.44*g*mol^-1=0.140*g$ .

What mass of solute is present in 24*mL24*mL of 0.10*mol*l^-10.10*mol*l^-1 aqueous sodium chloride solution?