What mass of solute is present in #24*mL# of #0.10*mol*l^-1# aqueous sodium chloride solution?

1 Answer
Apr 23, 2017

Answer:

Approx. #0.140*g#.

Explanation:

We have #0.1*mol*dm^-3# #NaCl#.

Now believe or not, #1*dm^3=1*L#, because the prefix #"deci"-=10^-1#

And so,...........#1*dm^3=(1xx10^-1*m)^3#

#=1xx10^-3*m^3-=1*L#, because there are #1000*L# in a #m^3#. A #"cubic meter"# is A HUGE VOLUME..........

And so we simply perform the product:

#"Mass of NaCl"="Concentration"xx"Volume"xx"molar mass, NaCl"#

#0.024*Lxx0.1*mol*L^-1xx58.44*g*mol^-1=0.140*g#.