Question #4eb61

1 Answer
Apr 26, 2017

Answer:

Mass #Al_2O_3# produced = 85 grams.

Explanation:

For reaction problems, convert all givens to moles and apply to rxn ratios of balanced equation.

#4Al^o(s)#........... +........ #3O_2(g)# => #2Al_2O_3(s)#
4moles ......................(excess) ..... 2moles

(45g/27g/mol)......................... => ...1/2(1.7mol)#Al_2O_3(s)#
= 1.7 mole #Al^o(s)#

=> moles #Al_2O_3(s)# is half as many moles as Al(s). => 0.833mole .=> #Al_2O_3(s)#

Convert to grams => 0.833 mole#Al_2O_3(s)#(102 g/mole) = 85g #Al_2O_3(s)#