Question

Question #88660

Answer 1

There will be a force of replusion, `F_r`, because both charges have the same sign. Coulomb's Law, in equation form, tells us that the repulsive force will be
`F_r = (k*q_1*q_2)/r^2`

Plugging in the data and working it out gives us

`F_r = (9.0times10^9 N*m^2/C^2*(-22.0times10^-9 C)*(-22.0times10^-9 C))/(0.06 m)^2`

`F_r = (9.0times10^9 N*m^2/cancel(C^2)*(-22.0times10^-9 cancel(C))*(-22.0times10^-9 cancel(C)))/(0.0036 m^2)`

`F_r = (9.0times10^9 N*cancel(m^2)*-22.0times-22times.010^-18 )/(0.0036 cancel(m^2))`

`F_r = (9.0times10^9 N*22.0times22.0times.010^-18 )/0.0036`

`F_r = (9.0 N*22.0times22.0times10^-9 )/0.0036 = 1,210,000 N`

`F_r = 1,210,000 N = 1.21times10^-3 N`

I hope this helps,
Steve