What is the molality of a 0.030⋅g mass of sugar dissolved in 300⋅mL of water?

1 Answer
anor277
May 3, 2017

Molality≡Moles of soluteKilograms of solvent

Explanation:

And so Molality=0.03⋅g180.16⋅g⋅mol−10.3⋅kg=??mol⋅kg−1.

At these concentrations the molality would be identical to the molarity.

Note that 1⋅dm3 is a fancy way of saying 1⋅L, 1⋅dm3 = 1 decimetre, where the prefix deci≡10−1.

And thus 1⋅dm3≡(10−1⋅m)3=10−3⋅m3=1⋅L, because there are 1000⋅L⋅m−3. A cubic metre is a huge volume.

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