# What is the "VSEPR" treatment of "hydrazine"?

May 1, 2017

There are $4 \times 1 + 2 \times 7 = 18 \cdot \text{electrons}$ to distribute around 6 centres........

#### Explanation:

And so for hydrazine, we write,

${H}_{2} \ddot{N} - \ddot{N} {H}_{2}$; these represent 14 valence electrons, $4 \times N - H$, and $1 \times N - N$, and $2 \times N$ lone pairs.

The remaining 4 electrons are conceived to be the inner core electrons on the nitrogen centre (i.e. the original $1 {s}^{2}$ sets). Anyway, we have distributed 18 electrons as required, 14 are valence electrons. Capisce?

What is the geometry about the nitrogen centres?