# Question #bbed8

##### 1 Answer

It has nothing to do with ions or anything like.

**Where J is current density**

I **is the charge in the total area**

This means more the current density more the current

**As a simple example, assume the current density is uniform (equal density) across the cross section of a wire with area #3 m^2#. Suppose that the total current flow is #I=3.2A.# What is the current density?**

Calculate area from radius

Increasing the current

zappppp!!!!!!!

**Now assume the current density is uniform (equal density) across the cross section of a wire with area #3 m^2#. Suppose that the total current flow is #I=18A.# What is the current density**

So increasing the current density means that you are actually increasing the current if you assume that the area of the conductor is remaining the same

In electrolysis if you apply more energy obviously the electrolysis would be faster. This is for every device that uses energy including us. More energy more work.Electrolysis is actually a reaction which cannot start on its own.But it can be considered as a reaction.

Like in reactions in electrolysis too bonds are broken are formed into new chemical bonds. But to break a bond you need to apply some energy and this amount of energy or the energy to break a bond is known as **bond dissociation energies**. This energy comes from the electrical source. So more energy the faster the process

Now let me show you an example

**Suppose that #2C#/s is applied to a solution of #CuSO4# solution for 2 seconds. Recall that 1A = 1C/s**

The reaction

=

Net ionic reaction

Each mole of

Thus

The whole reaction

As 2C/s is applied for 2s

**Use the Faraday's constant to calculate the moles of electrons lost and gained in total.**

**1 mole of #Cu^(2+)# is reduced per 2 mole electrons**

**Thus moles of #Cu# formed**

Now see what happens if we apply more charge

Consider the charge as 3C/s for 2s

Do the same calculations

As 3C/s is applied for 2s

=

Thus more the current,voltage and coulomb the more the mole of copper formed thus more the mass of copper formed

mole to grams

Plotting a graph

If my handwriting is too bad

y = mol of Cu formed from reduction of

x = mol of electrons used in the process