Question #e6ee7

1 Answer
Eddie
May 5, 2017

The power will be the energy per photon, # (hc)/lambda#, times the number, #n#, of photons emmitted each second:

#P = n (hc)/lambda#

#implies n = (P lambda)/(hc) = (330 xx 600*10^(-9))/(6.63*10^(-34) xx 3* 10^8) approx 10^(21) \ s^(-1) #

Related questions
Impact of this question
725 views around the world
You can reuse this answer
Creative Commons License