# Question 80a54

May 7, 2017

You have copied the question wrong.

$V {O}_{2}$ is a not an ion. It is a compound formed by the following reaction and compounds have a charge of 0. It forms $V {O}^{+ 2}$ when dissolved in non-oxidising acids such as $H C l$

V_2O_5 + V_2O_3 → 4 VO_2#

So actually the equation is

$x + \left(\left(- 2\right) + \left(- 2\right)\right) = 0$
$x + \left(- 4\right) = 0$
$x = 4$