A #2.5*L# volume of gas at #800*mm*Hg# pressure, is expanded with constant temperature to a #5.0*L# volume. What is the resultant pressure of the gas?

1 Answer
May 8, 2017

Answer:

Well #P_1V_1=P_2V_2...........# given constant #T#, which is old #"Boyle's Law".................#

Explanation:

And so #P_2=(P_1V_1)/V_2=(800*mm*Hgxx0.250*L)/(0.500*L)=#

#400*mm*Hg#.

Just to ADD that you DO NOT measure a pressure in #mm*Hg# OVER #1*atm# (#1*atm-=760*mm*Hg#). This is an inappropriate question posed by someone who has NEVER used a mercury manometer, and certainly NEVER cleaned up a mercury spill.