How many moles of dichromate ion are necessary to oxidize #10*mol# of #Pb^(2+)# ion to #Pb^(4+)# ion?

1 Answer
May 14, 2017

Answer:

Well, we need to write the redox equation............

Explanation:

#Cr_2O_7^(2-) +14H^+ + 6e^(-)rarr 2Cr^(3+) +7H_2O# #(i)#

And #Pb^(2+)# may be oxidized to #Pb^(4+)#....

#Pb^(2+) rarr Pb^(4+) + 2e^-# #(ii)#

And so add #(i) + 3xx(ii)# to give.............

#Cr_2O_7^(2-) +14H^+ + 3Pb^(2+)rarr 2Cr^(3+) +3Pb^(4+) + 7H_2O#

And if this redox couple works, and I have no idea whether it does, we would have to use #3.34*mol# dichromate ion........