# Question #ab462

May 15, 2017

$= 2 x \sqrt{3 x y} + 3 x \sqrt{2 y}$

#### Explanation:

Write each term under a root as the product of its factors, using squares where possible.

$\sqrt{12 {x}^{3} y} - x \sqrt{50 y} + \sqrt{128 {x}^{2} y}$

$= \sqrt{4 \times 3 \times {x}^{2} \times x y} - x \sqrt{25 \times 2 y} + \sqrt{64 \times 2 {x}^{2} y}$

Find the square roots where possible.

$= 2 x \sqrt{3 x y} - 5 x \textcolor{b l u e}{\sqrt{2 y}} + 8 x \textcolor{b l u e}{\sqrt{2 y}}$

$= 2 x \sqrt{3 x y} + 3 x \sqrt{2 y}$