# How does ammonium hydroxide react with sulfuric acid?

May 18, 2017

Please notice that the anions swap places from the left side to the right side; this makes it a Double Displacement reaction.

May 18, 2017

This is an acid base reaction...........

#### Explanation:

When we write $N {H}_{4} O H$, i.e. $\text{ammonium hydroxide}$, we really mean ${H}_{3} N \cdot O {H}_{2}$, i.e. aqueous ammonia. Concentrated ammonia solution in water (the type that is retailed) is approx. $15 \cdot m o l \cdot {L}^{-} 1$ with respect to ammonia.

Now of course, as a weak base, there is SOME ammonium ion in solution according to the following equilibrium:

$N {H}_{3} \left(a q\right) + {H}_{2} O \left(l\right) r i g h t \le f t h a r p \infty n s N {H}_{4}^{+} + H {O}^{-}$,

but the equilibrium lies to the left, and the dominant species in solution is $N {H}_{3} \left(a q\right)$.

And so we could rewrite the reaction as:

${H}_{2} S {O}_{4} \left(a q\right) + 2 N {H}_{3} \left(a q\right) \rightarrow 2 N {H}_{4}^{+} + S {O}_{4}^{2 -}$.

We could isolate the salt $\text{ammonium sulfate}$, ${\left(N {H}_{4}\right)}_{2} S {O}_{4}$ from such a solution. Ammonium sulfate is a ubiquitous agricultural fertilizer.