# Question f1fb8

May 19, 2017

$\left(+ 50\right)$ or $\left(8 \times {10}^{-} 18 C\right)$
It was neutral with $500$ electrons, if it has lost 10% electrons, then it has lost $50$ electrons (10%# is the same as $\frac{10}{100}$ which is $0.1$, $500 \times 0.1 = \textcolor{g r e e n}{50}$)
If it has "lost" $\textcolor{g r e e n}{50}$" electron" then its charge will be $+ \textcolor{g r e e n}{50}$ (each electron is $- 1$ "lost")
Or in Coulombs the charge will be $\textcolor{red}{1.6 \times {10}^{-} 19} \cdot \textcolor{g r e e n}{50}$ which is $8 \times {10}^{-} 18 C$ (because each electron is $- 1.6 \times {10}^{-} 19 C$ in charge)