Question #4bc86

1 Answer
May 28, 2017

Answer:

#C_f=90.5%#

Explanation:

Given 1st order reaction => ?% of original sample remains after 1 hour?

Use the 1st order decay equation #C_f = C_oe^(-kt)#
#C_f#= Final Concentration = ?
#C_o#= Initial Concentration = 100%
#t=time # = 1 hour
#k=0.693/t_(1/2)# = #(0.693)(1/(10min))((60min)/(hr)) = 4.158hr^(-1)#
#C_f# = #(100%)e^-[(4.158hr^-1)(1.00hr)]#=#1.56%#Remaining