Which lanthanides are exceptions to the Aufbau principle?

1 Answer
Aug 24, 2017

See here for a fuller explanation on the lanthanides and actinides.

The order by atomic number is down the first column, and then down the second column. In #color(red)("red")# are the 'Aufbau exceptions'.

#color(white)([(color(red)(La),(color(red)([Xe] 6s^2 5d^1)),color(black)(Tb),(color(black)([Xe] 6s^2 4f^9))),(color(red)(Ce),(color(red)([Xe] 6s^2 4f^1 5d^1)),color(black)(Dy),(color(black)([Xe] 6s^2 4f^10))),(color(black)(Pr),(color(black)([Xe] 6s^2 4f^3)),color(black)(Ho),(color(black)([Xe] 6s^2 4f^11))),(color(black)(Nd),(color(black)([Xe] 6s^2 4f^4)),color(black)(Er),(color(black)([Xe] 6s^2 4f^12))),(color(black)(Pm),(color(black)([Xe] 6s^2 4f^5)),color(black)(Tm),(color(black)([Xe] 6s^2 4f^13))),(color(black)(Sm),(color(black)([Xe] 6s^2 4f^6)),color(black)(Yb),(color(black)([Xe] 6s^2 4f^14))),(color(black)(Eu),(color(black)([Xe] 6s^2 4f^7)),color(black)(Lu),(color(black)([Xe] 6s^2 4f^14 5d^1))),(color(red)(Gd),(color(red)([Xe] 6s^2 4f^7 5d^1)),"","")])#

Generally the electron configuration exceptions occur

  • early in the lanthanide series (lanthanum, cerium)
  • after filling the #4f# orbitals halfway (gadolinium).

http://onlinelibrary.wiley.com/doi/10.1002/9781118688304.ch8/summary, pp. 199 - 202

In general, it has to do with the closeness in energy of the #4f#, #5d#, and #6s# orbitals. The #5d# and #6s# are nearly the same energy across the entire lanthanide row, and the #4f# is fairly close in energy for the first few lanthanides.

That gives rise to the following rationales:

  • #"La"# and #"Ce"# have an electron in their #5d# instead of #4f# because the #4f# is more radially compact, and given the small difference in energy between them (about #"6.8 eV"#), it is more energetically favorable to choose the #5d#, which is radially more diffuse.

  • #"Gd"# has about a #"16 eV"# #4f-5d# energy gap, and apparently, the electron repulsion it would generate to add another #4f# electron, combined with the radial compactness of the #4f# orbitals, is enough that it would rather have that electron in the #5d#.