# Question #2df8a

Jun 10, 2017

The pressure is $= 95 k P a$

#### Explanation:

We apply Boyle's Law

${P}_{1} {V}_{1} = {P}_{2} {V}_{2}$

The initial pressure is ${P}_{1} = 45 k P a$

The initial volume is ${V}_{1} = 19 L$

The final volume is ${V}_{2} = 9 L$

The final pressure is

${P}_{2} = {V}_{1} / {V}_{2} \cdot {P}_{1}$

$= \frac{19}{9} \cdot 45 = 95 k P a$