Question

Question #fae85

Answer 1

The rates are `1.4 × 10^"-3"color(white)(l) "mol·L"^"-1""s"^"-1", 1.3 × 10^"-3"color(white)(l) "mol·L"^"-1""s"^"-1"`, and `1.0 × 10^"-3"color(white)(l) "mol·L"^"-1""s"^"-1"`, respectively.

Explanation:

The formula for the rate is

`color(blue)(bar(ul(|color(white)(a/a)"rate" = "-"(Δ["N"_2"O"_5])/(Δt) = "-"(["N"_2"O"_5]_2 - ["N"_2"O"_5]_1)/(t_2 - t_1)color(white)(a/a)|)))" "`

0 s to 195 s

`"rate" = "-"("2.10 mol/L - 2.37 mol/L"/("195 s - 0 s")) = -("-0.27 mol/L")/"195 s"`

`= 1.4 × 10^"-3"color(white)(l) "mol·L"^"-1""s"^"-1"`

195 s to 416 s

`"rate" = "-"("1.82 mol/L - 2.10 mol/L"/("416 s - 195 s")) = -("-0.28 mol/L")/"221 s"`

`= 1.3 × 10^"-3"color(white)(l) "mol·L"^"-1""s"^"-1"`

416 s to 725 s

`"rate" = "-"("1.50 mol/L - 1.82 mol/L"/("725 s - 416 s")) = -("-0.32 mol/L")/"309 s"`

`= 1.0 × 10^"-3"color(white)(l) "mol·L"^"-1""s"^"-1"`

Note: The data justify only two significant figures.

You may have to recalculate if Sapling expects three significant figures.