# If the boiling point increases by #"0.126 K"# for a solution of a nonelectrolyte in benzene, what molality was required? #K_b = "2.52 K" cdot "kg/mol"#.

##### 1 Answer

Jun 23, 2017

We assume the process is at

The **boiling point elevation** is given by

#DeltaT_b = T_b - T_b^"*" = iK_bm# ,where:

Benzene is the solvent to this nonelectrolyte. So, the **molality** is given by

#color(blue)(m) = (DeltaT_b)/(iK_b)#

#~~ (0.126 cancel"K")/(1cdot2.52 cancel"K"cdot"kg/mol")#

#~~# #color(blue)("0.05 mol/kg")#