Question #2b3b7

1 Answer
Maxwell
Jul 9, 2017

14.3 days

Explanation:

Since we know the "half life" of "Phosphorus-32" is "14.3 days" and the definition of half life is the the amount of time it takes for the initial sample to decay to half its amount, then we also can establish the following:

color(white)(----)color(blue)["1 gram"color(white)(.)stackrel"decays"-> "0.5 grams = 1 half life has occurred"

and since color(red)["1 half life = 14.3 days", it would take about color(red)["14.3 days" for the initial sample to decay to half its amount.

Related questions
See all questions in Nuclear Half-Life Calculations
Impact of this question
2023 views around the world
You can reuse this answer
Creative Commons License