A gas confined to a piston is subjected to a pressure that is THREE TIMES as great as the initial pressure. How does the volume evolve given constant temperature?

1 Answer
Jul 15, 2017

Answer:

Should not the volume REDUCE to a third of the original volume?

Explanation:

Old Boyle's Law holds that #PV=k# at constant temperature and constant amount of gas......

And thus #P_1V_1=P_2V_2#..................given that we describe a piston containing the SAME amount of gas.........

And if we solve for #V_2=(P_1V_1)/P_2=(P_1V_1)/(3P_1)=1/3*V_1# (because we specify that #P_2=3xxP_1#).

Does this make sense intuitively, given that we compress a gas at constant temperature?