Question #b80b1

1 Answer

Answer:

#[OH^-] = 3 xx 10^(-12)#

Explanation:

Since pH + pOH = 14 for all the aqueous solutions

pOH = 14-pH = 11,5

Since
in first approximation #pOH = -log[OH^-]#
therefore #[OH^-] = 10^(-pOH) = 10^(-11,5) = 3 xx 10^(-12)#