Question #611ac

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Answer 1 · 2017-07-18T07:50:46

The mass of the sample will be #=37g#

The half life of #U-238# is #t_(1/2)=4.510^9y#

This means that every #4.5*10^9y#, a sample will loose, #50%# of its mass.

The time here is

#t=4.510^9y#

#t=t_(1/2)#

The time is equal to the half life. We will loose #50%# of the original mass.

So,

The mass of the sample will be #=74/2=37g#