Question

Question #7619b

Answer 1

`(-oo,0)`

Explanation:

Range of `x - floor(x)` is `[0,1)`

`0` is not in the domain of `ln`, and as `x` gets close to `0`, `lnx` decreases without bound (goes to `-oo`).

`ln1 = 0`, but `x - floor(x)` never takes on the value `1`, so

the range of `ln(x-floor(x))` is `(-oo,0)`