# Question #e2528

##### 1 Answer

Jul 21, 2017

I don't know what the mistake was, but you should have

#### Explanation:

If I understand what you're trying to do with "horizontal rectangles" You need:

The greater

The lesser

The area is #int_-1^0 (x_"right" - x_"left") dy, or

# = {: 3/2y+3/4y^2]_-1^0#

# = (0)-(-3/2+3/4) = 3/4#