Question #fb84b

1 Answer
Jul 22, 2017

Answer:

Good catch,the book should have included the solution species #"Sn"^{2+}#.

Explanation:

The iron metal is not in solution and thus should still be left out. Thus, properly,

#E=E^0-{RT}/{6F}ln({["Sn"^{4+}]^3}/{["Sn"^{2+}]^3["Fe"^{3+}]^2})#

Note that the tin ion concentrations can be rendered as a ratio between oxidized and reduced solution species:

#E=E^0-{RT}/{6F}ln[ { ( (["Sn"^{4+}])/(["Sn"^{2+}]))^3}/{["Fe"^{3+}]^2}]#