# Design a decay series for a nuclide?

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Take the sum of #A=20# , #B=14# , and #C=20# . Add the digits together, then add this result to #90# to get the atomic number of the element you are using. To get the mass number, add #D=22# , #E=02# , and #F=15# , then if it is over #30# subtract #30# until the result is below #30# . If the value is odd and not divisible by #4# , add #1# . Add this result to #230# to get the mass number.

Take the sum of

##### 2 Answers

Well, to find the atomic number, we add

#20 + 14 + 20 = 54#

The sum of these digits is

To find the mass number, we add

#22 + 02 + 15 = 39#

Since the result is over

(If you don't follow, I am literally following the directions on the image.)

So, we currently have

#bb(""_(Z)^(A_m) X = ""_(99)^(240) "Es")# ,

**einsteinium-240**. I'm guessing that's where you wanted me to stop.

Here's what I get.

#### Explanation:

**Identify the starting nuclide**

So, we must devise a decay series for

**1. Map a possible decay series**

**a.** Highlight the isotopes that represent the Belt of Stability

Here is a chart I created in Excel.

It shows in yellow the isotopes of the elements from lead to einsteinium, as listed in ptable.org.

**b.** Mark the box representing the starting nuclide

**c.** Mark each isotope in your decay series

The blue boxes represent a decay series that includes as many as possible of the isotopes in the Belt of Stability and ends with

**d.** Label the type of radiation emitted at each step

The particles emitted are

**2. Report the number of #α, β^"+"#, and #β^"-"# particles**

The decay chain involves the emission of eight α particles, four

**Note**: I much prefer an alternate pathway involving the red blocks in the diagram.

It involves the emission of eight α particles and one