What is the boiling point of an aqueous solution of #LiBr# that is #0.527*mol*kg^-1# with respect to the salt?

1 Answer
Aug 9, 2017

Answer:

This site lists #K_B#, the ebullioscopic constant of water, as #0.512*""^@C*kg*mol^-1#.....

Explanation:

We know that in aqueous solution the lithium bromide salt speciates to its constituent ions.........

#LiBr(s) stackrel(H_2O)rarrLi^+ + Br^(-)#

And #DeltaT_"boiling point elevation"=ixx"molal conc."xxK_B#

And #i=2# because of the speciation of the ionic solute......

#DeltaT=2xx0.527*mol*kg^-1xx0.512*kg*mol^-1*""^@C#

#=0.540# #""^@C#

And thus the observed boiling point of the solution should be #100.540# #""^@C#.