# How do I solve 4(x-3)-(x-5)=0?

Aug 14, 2017

$x = \frac{7}{3}$

Refer to the explanation for the process.

#### Explanation:

Solve:

$4 \left(x - 3\right) - \left(x - 5\right) = 0$

Expand.

$4 x - 12 - x + 5 = 0$

Simplify.

$3 x - 7 = 0$

Add $7$ to both sides.

$3 x = 7$

Divide both sides by $3$.

$x = \frac{7}{3}$