# Question #16f9b

Aug 16, 2017

Use heat balance & mass balance

#### Explanation:

The final volume of the mixture is $4 l$ assuming the density is constant. Then the heat balance is

$V \setminus \cancel{\setminus \rho {C}_{p}} {T}_{f} = {V}_{1} \setminus \cancel{\setminus \rho {C}_{p}} {T}_{1} + {V}_{2} \setminus \cancel{\setminus \rho {C}_{p}} {T}_{2}$

$4 {T}_{f} = 100 + 40 \cdot 3$

${T}_{f} = \frac{220}{4}$

${T}_{f} = {44}^{o} C$