# The pressure on a 22.5*L volume of gas enclosed in a piston is REDUCED from 748*mm*Hg to 725*mm*Hg. What is the new volume?

Aug 27, 2017

#### Answer:

Well, ${P}_{1} {V}_{1} = {P}_{2} {V}_{2}$.......and the VOLUME should INCREASE BECAUSE YOU DECREASE the PRESSURE......

#### Explanation:

And so....${V}_{2} = \frac{{P}_{1} {V}_{1}}{P} _ 2$, which clearly has the units of volume. Agreed?

V_2=(22.5*Lxx748*mm*Hg)/(725*mm*Hg)=??*L