# Question #cddba

Aug 31, 2017

Using conversion factors, we get $23 m L$.

#### Explanation:

We can answer this question using conversion factors.

In short, since we know that $1.48$ grams of the substance is equal to $1 c {m}^{3}$ of the substance, we know that $\frac{1 c {m}^{3}}{1.48 g} = 1$

Also, since $1 m L$ is equal to $1 c {m}^{3}$, we can say that $\frac{1 m L}{1 c {m}^{3}} = 1$

Then, all we need to do is multiply our value ($34 g$) by the conversion factors.

$34 \textcolor{g r e e n}{g} \cdot \frac{\textcolor{red}{1 c {m}^{3}}}{1.48 \textcolor{g r e e n}{g}} \cdot \frac{1 m L}{\textcolor{red}{1 c {m}^{3}}}$

The same-colored units cancel out, and we're left with:

$\frac{34 m L}{1.48}$

$34 m L$ has two significant figures, so we give our answer to two significant figures:

$23 m L$