Question

Question #66e5c

Answer 1

Well....the volume should be COMPRESSED down to approx. `100*mL`.

Explanation:

According to old Boyle's law, `P_1V_1=P_2V_2` at constant `T`.

We know that `1*atm` of pressure will support a column of mercury that is `760*mm` high....and we can use a mercury column as a measurement of pressure on this basis......

We solve for `V_2=(P_1V_1)/(P_2)`

`=((8.45*mm*Hg)/(760*mm*Hg*atm^-1)xx4.60*L)/((368*mm*Hg)/(760*mm*Hg))=??L`.

Answer 2

`0.1056L`

Explanation:

Using the Ideal Gas Laws,
`P_1V_1/T_1 = P_2V_2/T_2`, so at constant temperature we have

`P_1V_1 = P_2V_2` ; `(P_1V_1)/P_2 = V_2`

`V_2 = (8.45 xx 4.60)/368` ; `V_2 = 0.1056L`