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Question #26a42

1 Answer

Sep 4, 2017

In the first container the enclosed gas will exert a force per unit area of approximately $1.524 \cdot 10^{3}$ $1.524*10^3$ bar.

Explanation:

$P V = n R T$ $PV = nRT$

$P V = n R T = P V$ $PV = nRT = PV$

Thus,

$P_{1} V_{1} = P_{2} V_{2}$ $P_1V_1 = P_2V_2$

Math time:

$P_{1} \cdot 0.5650 L = 715.1 b a r \cdot 1.204 L$ $P_1*0.5650L = 715.1b ar* 1.204L$
$therefore P_1 approx 1.524*10^3$ bar

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