# Question #26a42

Sep 4, 2017

In the first container the enclosed gas will exert a force per unit area of approximately $1.524 \cdot {10}^{3}$ bar.

#### Explanation:

$P V = n R T$

$P V = n R T = P V$

Thus,

${P}_{1} {V}_{1} = {P}_{2} {V}_{2}$

Math time:

${P}_{1} \cdot 0.5650 L = 715.1 b a r \cdot 1.204 L$
$\therefore {P}_{1} \approx 1.524 \cdot {10}^{3}$ bar