# How do we represent the redox reaction between dichromate ion and ferrous ion stoichiometrically?

Sep 5, 2017

#### Answer:

$C {r}_{2} {O}_{7}^{2 -} + 6 F {e}^{2 +} + 14 {H}^{+} \rightarrow 2 C {r}^{3 +} + 6 F {e}^{3 +} + 7 {H}_{2} O \left(l\right)$

#### Explanation:

$\text{Reduction half-equation}$

$C {r}_{2} {O}_{7}^{2 -} + 14 {H}^{+} + 6 {e}^{-} \rightarrow 2 C {r}^{3 +} + 7 {H}_{2} O \left(l\right)$

$\text{Oxidation half-equation}$

$F {e}^{2 +} \rightarrow F {e}^{3 +} + {e}^{-}$

And so we takes one of the former and six of the latter......

$C {r}_{2} {O}_{7}^{2 -} + 6 F {e}^{2 +} + 14 {H}^{+} \rightarrow 2 C {r}^{3 +} + 6 F {e}^{3 +} + 7 {H}_{2} O \left(l\right)$