# What was the original volume of a gas that has changed from a pressure of 6.20 atm to 9.150 atm and a new volume of 322 mL?

Sep 6, 2017

The original volume was 475 mL.

#### Explanation:

Since only the pressure changes, we can use Boyle's Law to solve this problem.

Boyle's Law is

$\textcolor{b l u e}{\overline{\underline{| \textcolor{w h i t e}{\frac{a}{a}} {p}_{1} {V}_{1} = {p}_{2} {V}_{2} \textcolor{w h i t e}{\frac{a}{a}} |}}} \text{ }$

We can rearrange Boyle's Law to get

V_1 = V_2 × p_2/p_1

In this problem,

${p}_{1} = \text{6.20 atm"; color(white)(ll)V_1 = "?}$
${p}_{2} = \text{9.150 atm"; V_2 = "322 mL}$

${V}_{1} = \text{322 mL" × (9.150 color(red)(cancel(color(black)("atm"))))/(6.20 color(red)(cancel(color(black)("atm")))) = "475 mL}$