# What are the oxidation states of each element that comprise the interhalogen, I-F?

Sep 6, 2017

Well, fluorine usually assumes an oxidation state of $- I$....and it does so here.....

#### Explanation:

The sum of the oxidation numbers EQUALS the charge on the ion, and since we gots a neutral molecule, we have therefore $\stackrel{+ I}{I}$.

What are the oxidation numbers for the elements in ${F}_{2}$, and for both elements in $I {F}_{7}$?

Sep 6, 2017

Oxidation number of fluorine $= - 1$

#### Explanation:

Are you trying to spell Fluorine??

Well the Compound Name is Iodine mono fluoride or Iodine (I) fluoride $\left(\text{IF}\right)$

Since the Oxidation Number of Iodine is $1$

Hence...

Oxidation Number $\Rightarrow \text{IF} = 1 + F = 0$

$\textcolor{w h i t e}{\times \times \times \times \times x} \Rightarrow F = - 1$