What are the oxidation states of each element that comprise the interhalogen, #I-F#?

2 Answers
Sep 6, 2017

Answer:

Well, fluorine usually assumes an oxidation state of #-I#....and it does so here.....

Explanation:

The sum of the oxidation numbers EQUALS the charge on the ion, and since we gots a neutral molecule, we have therefore #stackrel(+I)I#.

What are the oxidation numbers for the elements in #F_2#, and for both elements in #IF_7#?

Sep 6, 2017

Answer:

Oxidation number of fluorine #= - 1#

Explanation:

Are you trying to spell Fluorine??

Well the Compound Name is Iodine mono fluoride or Iodine (I) fluoride #("IF")#

Since the Oxidation Number of Iodine is #1#

Hence...

Oxidation Number #rArr "IF" = 1 + F = 0#

#color(white)(xxxxxxxxxxx) rArr F = -1#