If #rho=3.97gcm^-3#, what is the mass of an object whose volume is #575*cm^3#?

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Answer 1 · 2017-09-15T17:46:15

@coleash711 you have already been given the formula for density....

#rho="Mass"/"Volume"#, and thus #"mass"="volume"xxrho#

#575*cm^3xx3.97*g*cm^-3="over 2 kg of sparkler......"#

If #rho=3.97*g*cm^-3#, what is the mass of an object whose volume is #575*cm^3#?