# If rho=3.97*g*cm^-3, what is the mass of an object whose volume is 575*cm^3?

$\rho = \text{Mass"/"Volume}$, and thus $\text{mass"="volume} \times \rho$
$575 \cdot c {m}^{3} \times 3.97 \cdot g \cdot c {m}^{-} 3 = \text{over 2 kg of sparkler......}$