# Question #06dc7

##### 1 Answer

#### Answer:

#### Explanation:

The idea here is that you need to figure out the **volume** of the cube first, then use that value to find the **density** of gold.

As you know, the volume of a cube is given by

#"volume cube" = l^3#

Here **side length** of the cube.

In your case, the volume of the cube will be equal to

#"volume cube" = ("1.55 cm")^3#

#"volume cube" = "3.724 cm"^3#

Now, in order to find the **density** of gold, *unit of volume* of gold.

Since you know that

#rho = "71.9 g"/"3.724 cm"^3#

This will get you

#rho = 71.9/3.724 * "1 g"/"1 cm"^3 = color(darkgreen)(ul(color(black)("19.3 g/cm"^3)))#

The answer is rounded to three **sig figs**.