Question #4eb4a

1 Answer
Sep 30, 2017

Answer:

See the answer below...
Think it to be #E/2#
Hope it helps...

Explanation:

Suppose,the spring #A# and #B# stretches by the length #x_1# and #x_2# unit.
We know that Increase in length is directly proportional to force applied but negative in sign.
So we can write,
#F=-kx_1# and #F=-2kx_2# [because each time force used is equal]
From the equation we can write that #-kx_1=-2kx_2=>x_1=2x_2#
Here,we also know for the spring #A# ,
#E=1/2kx_1^2#
So for the spring #B# the energy restored will be #1/2xx2kxxx_2^2=>1/2xx2kxxx_1^2/4=E/2#