# Question #f4e73

Dec 28, 2017

Kinetic energy will become 8 times than first.

#### Explanation:

Kinetic energy(KE) $= \frac{1}{2} m {v}^{2}$
Let initial KE be $K {E}_{i}$ and final KE be $K {E}_{f}$

$\frac{K {E}_{i}}{K {E}_{f}} = \frac{\frac{1}{2} {m}_{i} {v}_{i}^{2}}{\frac{1}{2} {m}_{f} {v}_{f}^{2}}$

$\frac{K {E}_{i}}{K {E}_{f}} = \frac{2 {m}_{i} {v}_{i}^{2}}{16 {m}_{i} {v}_{i}^{2}}$

$\frac{K {E}_{i}}{K {E}_{f}} = \frac{1}{8}$

$K {E}_{f} = 8 K {E}_{i}$

So, kinetic energy will become 8 times than first.