# Question #6c882

Oct 12, 2017

$- 1 \left({b}^{2} + {a}^{b} + 24\right)$

#### Explanation:

The only factor that the three terms share is $- 1$, and there isn't a good way to separate them so that it produces two binomials which multiply together to produce $- {b}^{2} - {a}^{b} - 24$. Therefore, the only factoring that can be done is to pull the $- 1$ factor out of all 3 terms like this:

$- {b}^{2} - {a}^{b} - 24$

$\left(- 1\right) \left({b}^{2}\right) + \left(- 1\right) \left({a}^{b}\right) + \left(- 1\right) \left(24\right)$

$- 1 \left({b}^{2} + {a}^{b} + 24\right)$