Question #3f803

3 Answers
Oct 7, 2017

#x=-2#

Explanation:

#-3x-15=3x-3# by removing brackets in both sides.
#-15+3=3x+3x# by bringing x terms to one side and constant the other side.
#6x=-12# or #x=-(12/6)=-2#

Oct 7, 2017

#x=-2#

Explanation:

#"using the "color(blue)"distributive property"#

#•color(white)(x)a(b+c)=ab+ac#

#"apply this concept to the brackets on both sides of the"#
#"equation"#

#rArr-3x-15=3x-3#

#"collecting terms in x on the left side and numeric values"#
#"on the right side"#

#"subtract 3x from both sides"#

#-3xcolor(red)(-3x)-15=cancel(3x)cancel(-3x)-3#

#rArr-6x-15=-3#

#"add 15 to both sides"#

#-6xcancel(-15)cancel(+15)=-3color(red)(+15)#

#rArr-6x=12#

#"divide both sides by "-6#

#(cancel(-6) x)/cancel(-6)=12/(-6)#

#rArrx=-2#

#color(blue)"As a check"#

Substitute this value into the equation and if both sides are equal then it is the solution.

#"left "=(-3xx3)=-9#

#"right "=(-3xx3)=-9#

#rArrx=-2" is the solution"#

Oct 7, 2017

#x=-2#

Explanation:

If we look at just #-3(x+5)# for now, you have to multiply each part in the parenthesis by what it's all being multiplied by. In this case, when we multiply #x# by #-3#, it's #-3x#, then the #5# times the same is #-15#.

So the first side is now

#-3x-15#

We do the same for the other side resulting in

#3x-3#

So now we have

#-3x-15=3x-3#

We get all the #x#'s together by adding #3x# to both sides to remove it from the left and adding to the right resulting in

#-15=6x-3#

We then add #3# to both sides to remove it from the right and add to the left resulting in

#-12=6x#

Now we can solve for #x# by dividing both sides by #6#, resulting in

#-2=x#