# Question #be455

##### 1 Answer

Jan 9, 2018

#### Answer:

#### Explanation:

#"here are two possible approaches "#

#color(blue)"Approach 1"#

#"add the fractions on the left "#

#"the "color(blue)"lowest common multiple of 3 and 2 is 6"#

#rArr5/3xx2/2p=10/6p" and "3/2xx3/3p=9/6p#

#rArr10/6p+9/6p=19/10#

#rArr(19p)/6=19/10#

#"multiply all terms by 30"#

#cancel(30)^5xx(19p)/cancel(6)^1=cancel(30)^3xx19/cancel(10)^1#

#rArr95p=57#

#"divide both sides by 95"#

#rArrp=57/95=3/5#

#color(blue)"Approach 2"#

#"multiply all terms by the lowest common multiple"#

#"the lowest common multiple of 3, 2 and 10 is 30"#

#rArr50p+45p=57#

#rArr95p=57#

#rArrp=57/95=3/5#