# Question ae1fc

Nov 5, 2017

$64 + 32 x + 4 {x}^{2}$

#### Explanation:

According to the order of operations:

First: terms/factors between brackets, which is: $4 + x$, but you can't solve this furthermore, so you leave it like this.

Second: powers or square roots, which is ${\left(4 + x\right)}^{2}$. It's a special product (a perfect square trinomial). So it becomes

16 + 8x + x²#

since ${\left(a + b\right)}^{2} = \left({a}^{2} + 2 a b + {b}^{2}\right)$

Third: multiplications or divisions, which is $4 {\left(4 + x\right)}^{2}$ We already calculated that

${\left(4 + x\right)}^{2} = 16 + 8 x + {x}^{2}$

So then multiply the whole polynomial with $4$

$4 \cdot 16 + 4 \cdot 8 x + 4 \cdot {x}^{2} = 64 + 32 x + 4 {x}^{2}$

Fourth: additions or subtractions, you don't have any. So

$64 + 32 x + 4 {x}^{2}$