Question #bccac
2 Answers
By converting the equation in point-slope form to slope-intercept form, we obtain
Explanation:
Given the slope of a line and a point on it, we can write its equation in point-slope form, denoted by:
Where
Let’s plug those values in:
We can now move around terms to convert this to slope-intercept form:
Explanation:
#"the equation of a line in "color(blue)"slope-intercept form"# is.
#color(red)(bar(ul(|color(white)(2/2)color(black)(y=mx+b)color(white)(2/2)|)))#
#"where m is the slope and b the y-intercept"#
#"here "m=8/9#
#rArry=8/9x+blarrcolor(blue)"is the partial equation"#
#"to find b substitute "(6,-8)" into the partial equation"#
#-8=(8/9xx6)+brArrb=-8-16/3=-40/3#
#rArry=8/9x-40/3larrcolor(red)"in slope-interceot form"#