# 6 = sqrt( 2z - 3) - 3? solve the equation

Apr 11, 2017

$z = 42$

#### Explanation:

Assuming your question is $6 = \sqrt{2 z - 3} - 3$

add $3$ to both sides
$6 + 3 = \sqrt{2 z - 3} - 3 + 3$
$9 = \sqrt{2 z - 3}$

square to both sides
${9}^{2} = {\left(\sqrt{2 z - 3}\right)}^{2}$
$81 = 2 z - 3$

add $3$ to both sides
$81 + 3 = 2 z - 3 + 3$
$84 = 2 z$

divide $2$ to both sides
$\frac{84}{2} = \frac{2 z}{2}$

$42 = z$