# A 10.0 g sample of water at 50°C and 10.0 g sample of iron at 10°C are placed in a beaker together. What will happen to the temperature of the water?

Dec 29, 2017

Final temperature of water will be 46.11 degrees.

#### Explanation:

Energy in water $E = m \times C \times T$
x will be the final temperature (For specific heat coefficients: http://www.kentchemistry.com/links/Energy/SpecificHeat.htm):

$10 \times 0.45 \times \left(x - 10\right) = 10 \times 4.18 \times \left(50 - x\right)$

$4.5 x - 45 = 2090 - 41.8 x$

The final temperature of water and iron will be the same.

$4.5 x + 41.8 x = 2090 + 45$

$46.3 x = 2135$

$x = 46.11$ degrees. Final temperature.